648p^2=128

Solution for 648p^2=128 equation:

648p^2=128

We move all terms to the left:

648p^2-(128)=0

a = 648; b = 0; c = -128;
Δ = b2-4ac
Δ = 02-4·648·(-128)
Δ = 331776
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{331776}=576$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-576}{2*648}=\frac{-576}{1296}
=-4/9
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+576}{2*648}=\frac{576}{1296}
=4/9
$